Awater bed weighs 1025 n, and is 1.5 m wide by 2.5 m long. how much pressure does the water bed exert if the entire lower surface of the bed makes contact with the floor? a. 3.6 x 10^2 pa b. 2.7 x 10^4 pa c. 1.2 x 10^3 pa d. 2.7 x 10^2 pa

By definition we have to:
 
 Where,
 F: Force
 A: area
 For the area we have:
 
 Where,
 w: width
 l: long
 Substituting values we have:
 
 Substituting the values we have:
 
 Rewriting we have:
 
 
 d.
 2.7 x 10 ^ 2 Pa

D) 2.7 * 10² Pa

Explanation:
To answer this question, we will use the following equation:
pressure = 

1- getting the area:
The water bed is in the form of a rectangle. Therefore, the area can be calculated as follows:
area = length * width
We are given that:
lenth = 2.5 m
width = 1.5 m
This means that:
area = 2.5 * 1.5 = 3.75 m²

2- getting the pressure:
We noted that:
pressure = 

We have the force = 1025 N
We calculated the area = 3.75 m²

Substitute in the above equation to get the pressure as follows:
pressure = 
pressure = 2.7 * 10² Pa

Hope this helps :)

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