An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s. if the accepted value for the wave speed is 63 m/s, what is the percent error? 0.045% 0.048% 4.5% 4.8%

4.8%

Explanation:

percentage error can be calculated as the difference between the theoretical and experimental value divided by the experimental value expressed in percentage.

The percentage error can be  computed mathematically as

(accepted value - experimental value)/accepted value × 100

accepted value = 63 m/s

experimental value = 66 m/s

difference = 63 - 66 = -3 m/s

use the absolute value = 3 m/s

percentage error = (accepted value - experimental value)/accepted value × 100

percentage error = 3/63 × 100

percentage error = 300/63

percentage error = 4.76%

percentage error = 4.8%

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can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s