If a 375 ml sample of water was cooled from 37.5 c to 0 c how much heat wad lost in joules

The equation for heat is  
Q = m*Cp*del(T) where 
 Q = heat in Joules
 m = mass in kg
 Cp = the heat capacity of water at a constant pressure = 4,184 J/kgC
 del(T) = the change in temperature in either K or degrees C 
 1 liter of water = 1 kg at standard temperature and pressure. 
 375 mL water x (1 kg/1L water) = 0.375 kg water. 
 Q = (0.375 kg water)(4184 J/kgC)(37.5 C - 0 C) = 58,800 Joules.

The answer to this is decibel