How much heat is needed to change 5.42 grams of solid gold to liquid gold at its melting point of 1,063°c? the latent heat of fusion of gold is 66.6 j/g.

360.97 J

Explanation:

mass of gold, m = 5.42 g

Latent heat of fusion, L = 66.6 J/g

The amount of heat required to convert 1 kg of solid into liquid state at its melting point is called latent heat.

L = Heat / mass

So, L = Q / m

Q = m L

Where, Q is the amount of heat supplied and L be latent heat of fusion amd m be the mass of substance.

Q = 5.42 x 66.6

Q = 360.97 J

Thus, the amount of heat required to melt the desired amount of gold is 360.97 J.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft