A9.0 cm object is 3.0 cm from a lens, which has a focal length of –12.0 cm.

The question is missing, but I guess the problem is asking for the distance and the size of the image.

Let's find the distance first, by using the lens equation:

where f is the focal length, the distance of the object from the lens, the distance of the image from the lens. Using and , we find


where the negative sign means the image is virtual, so located in front of the lens.

Now we can find the size of the image, using the relationship:

where and are the size of the image and of the object, respectively.
By using , we can find , the size of the image:

where the positive sign means the image is upright.

The particles of the gas inside the ball heats up, bouncing off each other and spreading farther apart.hope my answer has you : )