Suppose you harvested a large crop of grain this year. the grain is now in a pile and takes up an area of 50 m2 and is 2 m high. you have a silo that has an area of 15 m2 that is 3 m high. will all of the grain fit in this silo? if not, how much of the grain will remain outside of the silo? show your work

I'm pretty sure that the silo has the shape of a cylinder.
So its volume is

          (area of the base) x (height)  =  (15 m²) x (3m) = 45 m³ .

I'm going to assume that the pile has taken the shape of a cone
on the ground, so its volume is

                 (1/3) x (area of the base) x (height)

              = (1/3) x (50m²) x (2m) = 33-1/3 m³  .

The whole answer to the question rests on the exact shape of
the pile of grain on the ground.  It could really help if somebody
could take a picture of the pile, so we could study the picture
here in Chicago, and estimate how closely the shape of the
pile resembles a cone.

If my assumption is valid, and the volume of grain in the pile
can be accurately calculated as the volume of a cone with the
same dimensions as the pile, then the grain will all fit in the silo
with no problem.  The silo will still be only 74% full, and it'll still
have room for another  11-2/3 m³  of grain.  

But if, say, the grain got wet and sticky as it was being poured
onto the pile, and the pile took the shape of a huge brick, then
its volume is  (area of the base) x (height) = 100 m³ .
If that's the shape of the pile, then only 45% of it will fit into the
silo.  The silo will be full and there'll still be 55 m³ of grain left
out on the ground to rot.

With the information that they sent to us up here in Chicago,
we simply don't know.

The characteristics of groundwater is said to be: are weak turbiditya constant temperaturechemical composition and almost overall absence of oxygen.