Am radio signals are broadcast at frequencies between 550 khz and 1600 khz and travel 2.99792 × 108 m/s. what is the shortest am wavelength? answer in units of m.

Λ = c/f; where λ is the wavelength, c is the velocity (3.0 ×10^8 m/s) and f is the frequency of the wave.
Therefore; λ1 = (2.99792×10^8)/5.5×10^5)
                      =  545.5 m
                   λ2 = (2.99792×10^8)/1.6×10^6
                       = 187.5 m
Therefore; the shortest wavelength is 187.5 m