During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet) the hammer falls in t sec is s = 16t2. what is the hammer's velocity when it strikes the ground?

The hammer's velocity when it strikes the ground is 128 ft/s.

Explanation:

Given that,

The distance (in feet) the hammer falls in t sec is given by the relation as :

The hammer is accidentally dropped from a height of 784 ft. We need to find the hammer's velocity when it strikes the ground. We know that the velocity of an object is equal to :

When the hammer strikes ground, s = 256 ft

So,

So, the velocity of the hammer when it strikes the ground is given by :

So, the hammer's velocity when it strikes the ground is 128 ft/s. Hence, this is the required solution.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

b

explanation: