If a heater took 4 minutes to convert 500g of liquid water to 500g of water vapour how long would the same heater take to convert 500g of liquid aluminium to 500g of aluminium gas

t₁ = time to convert liquid water to water vapor = 4 min = 4 x 60 = 240 sec

t₂ = time to convert liquid aluminium to aluminium gas = 4 min = ?

m₁ = mass of water = 500 g = 0.5 kg

L₁ = latent of vaporization = 2260000 J/kg

m₂ = mass of aluminium = 500 g = 0.5 kg

L₂ = latent of vaporization of aluminium = 10530000 J/kg

using conservation of heat

m₁ L₁ /t₁ = m₂ L₂ /t₂

(0.5) (2260000)/240 = (0.5) (10530000)/t₂

t₂ = 1118.23 sec

t₂ = 18.6 min