The power in a lightbulb is given by the equation p=i^2 r, where i is the current flowing through the lightbulb and r is the resistance of the lightbulb. what is the current in a circuit that has a resistance of 30.0 ω and a power of 55.0 w?

Current, I = 1.35 A

Explanation:

Given that,

Resistance of circuit, R = 30 ohms

Power of the circuit, P = 55 W

The power in a light bulb is given by the equation is :

I is the current in a circuit

I = 1.35 A

So, the current in a circuit is 1.35 A. Hence, this is the required solution.

f=ma newton's second law 7x8=56n

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