If a current of 80.0 ma exists in a metal wire, how many electrons flow past a given cross-section of the wire in 10.0 min? in what direction

The current I is the amount of charge Q that crosses a certain point of the wire in a time :

In our problem, the current is  and the time is , so the total charge flowing through the cross-section of the wire is


Each electron has a charge of , so the total number of electron is the total charge divided by the charge of one electron:


And the direction of the electron flow is opposite to the direction of the current, because for convention the current direction is taken as the direction of the positive charges, while electrons are negative charges.