Aflywheel with a radius of 0.700 m starts from rest and accelerates with a constant angular acceleration of 0.800 rad/s2 . part a part complete compute the magnitude of the tangential acceleration of a point on its rim at the start. atan = 0.560 m/s2 submitprevious answers correct part b part complete compute the magnitude of the radial acceleration of a point on its rim at the start. arad = 0 m/s2 submitprevious answers correct part c part complete compute the magnitude of the resultant acceleration of a point on its rim at the start. a = 0.560 m/s2 submitprevious answers correct part d compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0 â.

1) For a point on the rim of the flywheel, the distance from the center of the motion is equal to the radius of the wheel: .

The tangential acceleration for a point on the rim is given by

where  is the angular acceleration while r is the radius. Substituting the numbers, we get


2) The radial acceleration for a point on the rim (r=0.700 m) at time t=0 is given by:

where  is the tangential velocity at time t=0.

The tangential velocity is given by

where  is the angular speed; however, at the start of the motion (t=0) the flywheel is at rest, so  and , so the radial acceleration is .

3) The magnitude of the acceleration at time t=0 is given by:


4) As we said at point 1), the tangential acceleration is given by

but , the angular acceleration, is constant, so the tangential acceleration after an angle of  is just equal to the tangential acceleration at the beginning of the motion: