Suppose you apply a flame and heat one liter of water, raising its temperature 10°c. if you transfer the same heat energy to two liters, how much will the temperature rise? for three liters? record your answers on the blanks in the drawing at the right.

(a) the water density is , and 1 liter corresponds to a volume of . Therefore we can find the mass of the water in the first case:


The amount of heat supplied to the water to raise its temperature by  is
(1)
where 
is the specific heat capacity of the water. 
Using the data, we find


We want to find the increase in temperature if we transfer the same amount of heat Q to 2 liters of water. The mass of 2 liters of water is

And so by re-arranging equation (1) we can calculate the new increase of temperature:


(b) Now we have 3 liters of water. SImilarly to point (a), the mass is now

And so, the increase in temperature if we use the same amount of heat as before is

It really doesn't matter for any of the questions that you've listed.

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then