Aconverging lens has a focal length of 19.0 cm. locate the images for the following object distances. a) 41 cm b) 14cm

We can solve both parts of the problem by using the lens equation:

where
f is the focal length
is the distance of the object from the lens
is the distance of the image from the lens

Let's also keep in mind that for a converging lens, the focal length is taken as positive, so f=+19.0 cm.

(a) In this case, . So, the lens equation becomes

And so the distance of the image from the lens is

where the positive sign means the image is real, i.e. is located behind the lens (opposite side of the real object)

(b) In this case, . So, the lens equation becomes

And so the distance of the image from the lens is

where the negative sign means the image is virtual, i.e. is located in front of the lens (i.e. on the same side of the real object)

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction