Akid moving 3.78 m/s jumps on a slip and slide (uk=0.111). after sliding 5.00 m, what is his velocity? unit=m/s

Newton's Second law of motion:
F=ma => a = F/m = -Uk*mg/m = -Uk*g = -0.111*9.81 = -1.089 m/s^2 (negative sign is because there will be deceleration).

Laws of motion:
v^2 = u^2 + 2ad , v= Final velocity, u= initial velocity, a = acceleration, d = distance moved.
Therefore,
v= Sqrt (u^2+2at) =Sqrt {3.78^2+(-1.089*2*5)} = 1.844 m/s

Each student aligns the edge of the object with the left edge of the ruler as shown above. all four students read the ruler with a measurement of 4.6 cm. which statement describes the data they collect? i believe the answer is: the data have poor precision and poor accuracy because of a systematic error.