Help meh pls A student determines the Density of a sample of Aluminum is 2.78 g/ml. The Actual/Accepted Value form the table reads 2.7 g/ml. Calculate the Percent Error.

A)3%

B)0.03%

C)0.029%

Percent error = the absolute value of (actual value - expected value) / (expected value)

Percent error = (2.7-2.78)/(2.78)

Percent error = 0.029

Let me know if this helps!

answer:

ok i will i'm just bored