For a normal distribution with u = 30 and o = 2.9, determine the Z-score of 28.5413.
Z-score =

-0.503

Explanation:

Z-score is expressed as:

Z-score = x - μ/σ

Given the following

x = 28.5413

μ = 30

σ = 2.9

Z-score = 28.5413-30/2.9

Z-score = -1.4587/2.9

Z-score = -0.503

Hence the z-score for the distribution is -0.503

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answer:

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explanation: