how many moles of electrons, n, are transferred in the following reduction-oxidation reaction? 2 mno4-(aq) + 16 h+(aq) + 10 cl-(aq) → 2 mn2+(aq) + 5 cl2(g) + 8 h2o(l)

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answer:

b. 69

explanation:

answer:

142.925

explanation:

6 x 19 = 114

114 x 84 = 9,576

9,576 ÷ 67 = 142.925 and so on many numbers.

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