The larger of two numbers exceeds 3 times the smaller number by 6. The sum of 3 times the larger number and
twice the smaller number is 62. Which equation correctly
identifies x as the smaller number?

x +  y = 6

3x + 2y = 32

Multiply the ist equation by 3: 3x + 3y = 18  Subtract one equation from the other:   y = - 14, then x = 6 - y = 20 Now take the values of x and y and make sure they solve the problem.

     if not then its this

Let the larger be h and the smaller be x;

h-3x=4

2h+4x=58

This is a pair of simultaneous equations;

Eliminating h by multiplying equation 1 by two;

2h-6x=8

2h+4x=58

Subtracting equation 1 from equation II;

-2x=50

x=-25

The smaller number is -25

Explanation:

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answer:

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explanation: