Calculate δh°f in kj/mol for benzene, c6h6, from the following data: 2c6h6(l) + 15o2(g) → 12co2(g) + 6h2o(l); δh° = -6534 kj δh°f(co2) = -393. 5 kj/mol; δh°f(h2o) = -285. 8 kj/mol.

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the answer is poetry : )

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