Drag and drop the correct answer into each box to complete the proof. Parallelogram k l m n where k n is parallel to l m and k l is parallel to m n given: parallelogram klmn prove: ∠n≅∠l and ∠m≅∠k statement reason parallelogram klmn given kl¯¯¯¯¯∥nm¯¯¯¯¯¯¯ and kn¯¯¯¯¯¯∥lm¯¯¯¯¯¯ definition of parallelogram m∠k+m∠n=180° m∠l+m∠m=180° m∠k+m∠l=180° response area m∠k+m∠n=m∠k+m∠l m∠l+m∠m=m∠k+m∠l substitution property of equality m∠n=m∠l m∠m=m∠k response area ∠n≅∠l and ∠m≅∠k response area.