A teacher used the change of base formula to determine whether the equation below is correct. (log subscript 2 baseline 10) (log subscript 4 baseline 8) (log subscript 10 baseline 4) = 3 which statement explains whether the equation is correct? the equation is correct since (log subscript 2 baseline 10) (log subscript 4 baseline 8) (log subscript 10 baseline 4) = log (2 times 10) times log (4 times 8) times log (10 times 4). = log (20) times log (32) times log (40). =3 the equation is correct since (log subscript 2 baseline 10) (log subscript 4 baseline 8) (log subscript 10 baseline 4) = startfraction log 10 over log 2 endfraction times startfraction log 8 over log 4 endfraction times startfraction log 4 over log 10 endfraction. = startfraction log 8 over log 2 endfraction. = 3 the equation is correct since (log subscript 2 baseline 10) (log subscript 4 baseline 8) (log subscript 10 baseline 4) = startfraction log 10 over log 2 endfraction times startfraction log 8 over log 4 endfraction times startfraction log 4 over log 10 endfraction. = startfraction log 8 over log 2 endfraction. = 4. The equation is not correct since (log subscript 2 baseline 10) (log subscript 4 baseline 8) (log subscript 10 baseline 4) = log startfraction 10 over 2 endfraction times log eight-fourths times log four-tenths. = log 5 times log 2 times log 0. 4. = negative 0. 8.