The enormous state university history department offers three courses—ancient, medieval, and modern history—and the chairperson is trying to decide how many sections of each to offer this semester. the department is allowed to offer 42 sections total, there are 4,500 students who would like to take a course, and there are 55 professors to teach them. sections of ancient history have 100 students each, sections of medieval history hold 50 students each, and sections of modern history have 200 students each. modern history sections are taught by a team of two professors, while ancient and medieval history need only one professor per section. how many sections of each course should the chair schedule in order to offer all the sections that they are allowed, accommodate all of the students, and give one teaching assignment to each professor? hint [see example 2.] (assume each section has the maximum number of students allowed.)

A = 12

B = 18

C = 14

that's your solution.

number of sections is A + B + C which becomes 12 + 18 + 14 which is equal to 44

number of students in each course is 100A + 50B + 200C = 1200 + 900 + 2800 which is equal to 4900

number of teachers in each course is A + B + 2C which becomes 12 + 18 + 28 which is equal to 58.

12 sections in ancient history have 1200 students and 12 teachers.

that's 1 teacher per course and 100 students per section.

18 sections in medieval history have 900 students and 18 teachers.

that's 1 teacher per course and 50 students per section.

14 sections in modern history have 2800 students and 28 teachers.

that's 2 teachers per course and 200 students per section.

answer to your questions is:

12 sections of ancient history and 18 sections of medieval history and 14 sections of modern history.

the correct answer on edgen is:

(c.) prevent the spread of communism.

i just took the test.

you probably know the answer. stop asking stupid questions and making me waste my time. j.k. ; )   b.t.w. what are three ratios equivalent to 5 : 11? thx