If the elevator cable should break when the elevator is at a height h above the top of the spring, calculate the value that the spring stiffness constant k should have so that passengers undergo an acceleration of no more than 5.0 g when brought to rest. let m be the total mass of the elevator and passengers.

Explanation:

Given

Mass of Elevator is M

maximum acceleration is 5g

Cable breaks at a height of h above spring

Let K be the spring constant

For Elevator

Suppose spring compresses to a distance x

thus

Potential Energy is converted to Elastic Potential Energy

thus

1190

step-by-step explanation:

1400 - 15% to get the answer.

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