Why is it best to compare medians and interquartile ranges for these data, rather than comparing means and standard deviations? a. some of these data have outliers and/or are skewed, and the median and interquartile range amplify the effects of outliers and skewness. b. some of these data have vastly different centers, and the median and interquartile range provide more reliable information in these circumstances. c. these data are fairly symmetric and do not have outliers, and the median and interquartile range provide more reliable information in these circumstances. d. some of these data have outliers and/or are skewed, and the median and interquartile range are resistant to outliers.

A:some of the datas have outliers or are skewed,and the median and interquartile range amplify the effect of outliers and skweness

Explanation:datas are collated on every day basis around us,and the analysis if the data albeit effectively help us determine trends and proffer solution to issues.

Some data have extremely large figure relative to other data collected this are known as outliers e.g 1,2,3,4,59 represent data with an outlier ,59,effect of such abnormal figure or data gives a wrong or abnormal mean which will not potray the general essence of the figure but the application of mean and interquartile range will adequately potray a proper representative of the datas .

Same goes for a data that is not skewed,e.g -1,-2,1,2,3,4,5 is more of positive than negative any data calculated via mean will be positive and will not potray the negative figures in the data but median and interquartile will make provision for this unskewedness.

answer; criminal law;