Assume that the committee contains 8 men and 10 women and that three are selected at random for a subcommittee. What is the probability that the subcommittee consists of 2 men and 1 woman, given that it contains both men and women?

324/546 =  54/91

Explanation:

Using a brute force type of method in solving this problem.  There are eight possible outcomes which may be represented by

WWW   (failure)  

WWM    (failure)

WMW     (failure)

WMM     (success)   Probability =  (1/3) (10/14) (9/13)  =  90/546

MWW    (failure)

MWM    (success)    Probability  =  (2/3)(5/14) (9/13)   =  90/ 564

MMW    (success)    Probability  = (2/3) (9/14)(5/13)   =  144/ 564

MMM     (failure)

Where success is distinct as having a subcommittee with 1 woman and 2 men.   Adding up the all probabilities for the successes yields      324/546 =  54/91

my man just wants some puu

explanation:

if you have to make a general question and respond to your thoughts, then this isn't really a question someone can you on. read the passage, form your question, and answer using your thoughts. no one else can understand how you interpreted this text if you don't tell us.