For every football game there is a team that is expected to win by a certain number of points. In betting parlance, this is called the spread. If point spreads are accurate, we would expect about half of all games played to result in the favored team winning (beating the spread) and about half of all games to result in the team favored to not beat the spread. The accompanying data represent the results of 45 randomly selected games where a 0 indicates the favored team did not beat the spread and a 1 indicates the favored team beat the spread. Do the data suggest that sport books establish accurate spreads?

Full question attached

Answer and Explanation:

From the question,

Null hypothesis H0=0.5

Alternative hypothesis Ha≠0.5

Given that test statistic z = <p-p/√p(1-p)/n

<p is the sample proportion of favored teams= x/n = 25/45= 0.5556

p is the population proportion =0.50

n= population size/ number of games = 45

Z= 0.5556-0.50/√0.50(1-0.50)/45

= 0.5556-0.50/√0.50(0.50)/45

= 0.75

Two tailed test P-value from table given Z value 0.75

= 0.453

The p value is greater than level of significance 5%, 10% and so we don't reject null hypothesis. Also level of significance is not specified. Therefore option C is correct

what is the question?