In the adjoining figure, PRST is a parallelogram and PT is the median of triangle PQR. Prove that, Area of triangle PQT = Area of triangle STR.

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in triangle PQR,

PQ=PR [Given]

= angle PRQ=angle PQR[angle opposite to the equal sides are equal](1)

since ST|| QR and PQ is a transversal,then

angle PQR = angle PST (corresponding angles)(2)

since PQ || QR and PR is a transversal,then

angle PRQ=angle PST (corresponding angles)(3)

but angle PQR = angle PRQ , then from (2) and (3) we get

angle PST = angle PTS

In triangle PST

angle PST = angle PTS (proved)

So, PT = PS (sides opposite to equal angles are equal)

Or in shorter terms,

In traingle PSR And PTS

PQ=PR (given)

RS=PT (given)

Angle A is common

So,traingles are congruent(SAS) .

So corresponding sides QT=RS

the best and most correct answer among the choices provided by the question is the second choice "less supportive to the war of 1812"

the war of 1812 was a military conflict that lasted from june 1812 to february 1815, fought between the united states of america and the united kingdom, its north american colonies, and its native american allies.

i hope my answer has come to your . god bless and have a nice day ahead!