Um recipiente esférico possui um volume interno igual a 8 litros. suponha que se queira encher esse recipiente com gás nitrogênio, de modo que a pressão interna seja igual a 2,0 atm a uma temperatura de 27ºc. considerando a massa molecular do nitrogênio igual a 28 g/mol, a constante universal dos gases como 8,0j/(k. mol) e 1atm= 1x10-2 m³, calcule a massa desse gás que caberia no recipiente sob as condições citadas.

must usExplanation:This question refers to the study of gases. To solve it, initially we e the following expression:

P × V = n × R × T

where P is the pressure (Pa), V is the volume (m³), n is the number of moles in the sample, R is the universal gas constant and T is the temperature (K). Transforming the units according to the equation, we have:

P = 2 × 10 ^ 5 Pa

V = 8/1000 = 0.008 m³

T = 27 + 273 = 300 K

Substituting in the equation, we have:

2 × 10 ^ 5 × 0.008 = n × 8.0 × 300

n = 0.667 moles

Finally, we use the following expression, which relates number of moles and sample mass:

m = M × n

where m is the mass (g) and M is the molar mass (g / mol). Thus, the mass of this gas is:

m = 28 × 0.667

m = 18.67 g

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