Advanced Placement (AP), 15.10.2020 14:01 Aldcperformer

Question 25 The transfer of which of the following as part of the Columbian Exchange had the greatest effect on human migration patterns before 1800?
A Sugarcane
B
Potatoes
С
Cattle
D
Tobacco

Answers: 2

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The transfer that serves in 1800 as part of the Columbian Exchange that was considered as greatest effect that is been felt on human migration is :A Sugarcane.

Exchange of products out of the border of Columbia has been one of great influence to the economy of columbia.Before, 1800 one of the product that serves as exchange product which boast the economy of Columbia.

Therefore, option A is correct.

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Answer from: diawia

A. Sugarcane

Explanation:

The Columbian Exchange was named after the very popular voyager and explorer, Christopher Columbus. Columbian Exchange is also referred to as the Columbian Interchange and typically involved the widespread movement of commodities, plants, technology, cultures, diseases, people and animals across West Africa, the Atlantic, America and the Old world (Europe, Asia, and Africa) as far back as in the 15th and 16th century.

The transfer of sugarcane as part of the Columbian Exchange had the greatest effect on human migration patterns before 1800 because it was considered to be the main export commodity crops introduced from the Spanish West Indies. Therefore, many nations in Latin America, Asia and America based their economy on sugarcane production.

Hence, it negatively impacted human migration because it stimulated the formation of African trade slaves, used for the cultivation of sugar plantations.

Answer from: Quest

Im pretty sure it would be climax

Answer from: Quest

See diagram.we use washers to get the area and we will be integrating with respect to xouter radius is the distance between y = e^x and y = -1 $r_{\text{out} } = e^x ) = e^x + 1$ inner radius of washer is the distance between y = 1 and y = -1 $r_{\text{in} } = 1 - (-1) = 2$ the area of one cross-section of a washer is $\begin{aligned} a(x) & = \pi(r_{\text{out} } )^2 - \pi(r_{\text{in} } )^2 \\ & = \pi(e^x + 1 )^2 - \pi(2)^2 \\ & = \pi \big[(e^x + 1 )^2 - 4 \big] \end{aligned}$ solid lies between x = 0 and x = 2. the volume is $\begin{aligned} v & = \int_0^2 a(x) dx \\ & = \int_0^2 \pi \big[(e^x + 1 )^2 - 4 \big] dx \end{aligned}$ if you need this expanded, then $\begin{aligned} v & = \int_0^2 \pi \left(e^{2x} + 2e^x + 1 - 4 \right) dx \\ & = \int_0^2 \pi \left(e^{2x} + 2e^x -3 \right) dx \end{aligned}$ the question doesn't say to evaluate, so we're done.

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Question 25 The transfer of which of the following as part of the Columbian Exchange had the greate...

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