A130-lb person burns about 2300 calories to run a marathon how much energy is burned in kj chemistry

Data given

                 Energy burned in calorie = 2300 calorie

Required

              Energy burned in Kj = ?

Solution

               As we know that  

             1Cal = 0.0041868kj

            So 2300 Cal = 2300 x 0.0041868

            = 9.6294 Kj  (answer)

energy burned in kj = ?

As we know that  

1Cal= 0041868kj

So 2300 Cal= 2300 x 0.0041868 = 9.6294 Kj

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