In a population of rabbits, f (C1)(C1) = 0.28 and f (C2)(C2) = 0.72. The alleles exhibit an incomplete dominance relationship in which C1C1C1C1 produces black rabbits, C1C2C1C2 tan-colored rabbits, and C2C2C2C2 rabbits with white fur. If the assumptions of the Hardy-Weinberg principle apply to the rabbit population, what are the expected frequencies of: Part A black rabbits. Express your answer using two decimal places.

0.08

Explanation:

According to Hardy-Weinberg equilibrium, in absence of an evolutionary force allele frequencies in a population remain constant. In case of polyploid organisms, the formula for Hardy-Weinberg equilibrium is :

(p+q)^c = 1  where,

p = frequency of dominant allele

q = frequency of recessive allele

c = ploidy number

Here, the ploidy number is 4 since there are four chromosomes at a locus instead of the usual two.

f(C1)(C1) = 0.28

f(C2)(C2) = 0.72

Black rabbits = C1C1C1C1

Frequency of black rabbits= f(C1)(C1)*f(C1)(C1)

= 0.28 * 0.28

= 0.0784

= 0.08

i think that c)gold was found there

but i am not sure

nucleus

would be most reasonable answer tbh