A) Describe how EGF affects cell division.
B) Identify the role of each experiment in determining the difference in how cancer and normal cells
respond to EGF.
C) Calculate the mitotic index (number of cells in mitosis divided by total cells) for each kind of cell.
Compare the mitotic rates for each cell type
D) Predict the cause of rapid growth in the cancer cells observed in experiment 2. Justify your
answer with evidence and reasoning.

This is what I put (its kinda bad so don't judge)

Explanation:

A) Examining Table 1 with cancerous cells and HeLa cells we can see that with both HeLa and cancerous cells when treated with EGF increase in cells. Examining Table 2 we can see that HeLa cells create the most cells when treated with a concentration of 25 ug of EGF.

B) Normal cells increased by 33 when treated with a concentration of 10 ug of EGF. Cancerous cells increased by 405 when treated with a concentration of 10 ug of EGF. We can conclude from this that the cancerous cells multiply faster than normal cells with  a concentration of 10 ug of EGF.  

C) The mitotic index of HeLa cells with zero EGF treatment is 11 mitotic figures noted per 73 high power fields. The mitotic index of HeLa cells with 10 ug of EGF treatment is 8 mitotic figures noted per 90 high power fields. The mitotic index of cancerous cells with zero EGF treatment is 22 mitotic figures noted per 60 high power fields. The mitotic index of cancerous cells with 10 ug of EGF treatment is 27 mitotic figures noted per 465high power fields.  

I'm on D right now so I'll put that in when I'm done with it

lysosomes contain a variety of enzymes, enabling the cell to break down various biomolecules it engulfs, including peptides, nucleic acids, carbohydrates, and lipids (lysosomal lipase). the enzymes responsible for this hydrolysis require an acidic environment for optimal activity. hope i !

answer; i believe the correct answer is (sporophyte);