A multiple-channel queuing system with a Poisson arrival rate and exponential service time has an average arrival rate of four customers per hour and an average service time of 18 minutes per customer. The minimum number of servers required to avoid an overloaded system is

1.2

Explanation:

The computation of the minimum number of servers required to avoid an overloaded system is shown below:-

Average service time =  Average service time ÷ number of minutes in a hour

18 min = 18 ÷ 60 per hr

= 0.3 hr per customer

Now for four customers, it would be

min servers = 4 × 0.3

= 1.2

So, the correct answer is min servers = 2 as servers cant be in fractions

Therefore we have applied the above formula.

88 because 4 plus 4 equals 8. 40 plus 40 equals 80. 80 plus 8 equals 88

whole quiz

1. the sum of all activities involved in getting high-quality products into the marketplace

2.operations

3. the principle of looking at the supply chain as a whole in order to improve the overall flow through the system.

4. produced; performed

5. activities producing tangible products, such as radios, newspapers, buses, and textbooks.

6. activities producing intangible and tangible products, such as entertainment, transportation, and education.

7.   customer focus

8. analyzing a competitor's products to identify desirable improvements

9. the systematic direction and control of the processes that transform resources into finished projects that create value for and provide benefits to consumers.

10. operation management.

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