In the reaction 2kclo3(s) --> 2kcl(s) + 3o2(g) how many liters of oxygen gas at stp are produced from 31.9 g of kclo3?

Answers: -

8.75 L of O₂

Explanation: -

Molar mass of KClO₃ = 39 x 1 + 35.5 x 1 + 16 x 3 = 122.5 g

The balanced chemical equation for this process is

2KClO₃(s) --> 2KCl (s) + 3O₂(g)

From the balanced chemical equation we see

2 mol of KClO₃ gives 3 mol of O₂

At STP,

2 x 122.5 g of KClO₃ gives 3 x 22.4 L of O₂

31.9 g of KClO₃ gives 3 x 22.4 L of O₂ x

= 8.75 L of O₂

1. they vary with a higher number because boiling is way hotter than melting