If 0.0987 g h2o hydrolyzes, what is the theoretical yield of h2? 2h2o → → 2h2 + o2

The theoretical yield is 0.0110 g H₂.

Moles of H₂O = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O

Moles of H₂ = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂

Theoretical yield of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)

= 0.0110 g H₂

Theoretical yield of is 0.01 grams.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

According to stoichiometry:

2 moles of water produces = 2 moles of hydrogen

Thus 0.005 moles of water produces = moles of hydrogen

Mass of produced =

Thus theoretical yield of is 0.01 grams.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

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