Apressure cooker contains 0.355 mole of air, which occupies a volume of 5.68 liters. the temperature inside the pressure cooker is 394 k. what is the absolute pressure of the air in the pressure cooker?

We will use ideal gas equation in this problem

PV = nRT

Where

P = pressure of gas or air = ?

V = volume of air = volume of pressure cooker = 5.68 L

T = temperature = 394 K

n = moles of air = 0.355

R = ideal gas equation = 0.0821 L atm / mol K

Putting values

Pressure = nRT / V = 0.355 X 0.0821 X 394 / 5.68 = 2.02 atm.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.