Balance the equation __sio2 + __cac2 → __si + __cao + __co2

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

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5 SiO2 + 2 CaC2 = 5 Si + 2 CaO + 4 CO2

Balancing a chemical equation is to equalize the quantity of atoms of the elements present in the reagents with the quantity of these same atoms of the elements present in the products.

Reagents:                                       Products :

Si = 5*1 = 5                                     Si = 5 * 1 = 5

O = 5 * 2 = 10                                 Ca = 2 * 1 = 2

Ca = 2 * 1 = 2                                  O = 2 * 1 = 2

C = 2 * 2 = 4                                   C = 4*1 = 4

                                                      O = 4 * 2 = 8

Reagents = 5 + 10 + 2 + 4 = 21

Produts =  5 + 2 + 2 + 4 + 8 = 21

Hope that helps!

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.