Me if 3.00 g of ch3oh is reacted with excess sulfuric acid and the actual yield of (ch3)2so4 was 0.94 g, what was the percent yield of the reaction? 2 ch3oh + h2so4  → (ch3)2so4  + h2o

So yield = actual/predicted*100

You need to find the theoretical yield. CONVERT INTO MOLES. this is the 1st step you do in most calculation questions.

I got 15.92%

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.