Can someone me with these three questions, it will soon be due.

YOU also better mark me BRAINLIEST if someone else answers!!!

1)

volume = 100 mL

density = 1.02 g / mL

mass = density x volume

= 1.02 x 100 = 102 gCp = 4.03 J / oc gdT = 28.7 - 23.5 = 5.2 oCQ = m Cp dTQ = 102 x 4.03 x 5.2Q = 2138 JQ = 2.14 kJ

heat absorbed = 2.14 kJ

2)

We can calculate the moles of HC1 present in 50 ml 1m solution by using the formula, moles = volume of solution  in L*molarity moles = 50/1000 = .05 , L*1 M = .05 Moles of HCL. The same can be applied for calculation  of moles fo  Na OH of 50 ml, 1 M solution. (50 ml NaOH = .o5 L NaOH)Then use the formula = volume of solution / 1000*moles.wt,=1.825 gram. moles=mass in grams /moles.wt= .05 moles of HCIcalculate moles of water from this reaction.HC1+NaOH>NACl+h20 (Balanced Equation).5+.5> .5+.5.05 moles of waterDelta H=q/n.n=.05 to calculate the Delat H.

3) I don't understand it, sorry