If 4.66 moles of hcl reacts with excess mg(oh)2 how many moles of mgcl2 will be produced? (show work , you! )

The balanced chemical equation for the reaction is as follows

Mg(OH)₂ + 2HCl ---> MgCl₂ + 2H₂O

molar ratio of HCl to MgCl₂ is 2:1

There's excess Mg(OH)₂ therefore HCl is the limiting reactant.

the amount of product formed is determined by the amount of limiting reactant present

so when 2 mol of HCl reacts - 1 mol of MgCl₂ is produced

therefore when 4.66 mol of HCl reacts - 1/2 x 4.66 = 2.33 mol of MgCl₂ is produced

answer is 2.33 mol of MgCl₂

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