Chemistry, 19.12.2019 11:31 Tiff7859

Consider the reaction: i2(g)+cl2(g)⇌2icl(g) kp= 81.9 at 25 ∘c. calculate δgrxn for the reaction at 25 ∘c under each condition: -(part 1) at standard conditions -(part 2) picl= 2.63atm ; pi2= 0.324atm ; pcl2= 0.217atm .

Answers: 1

Show answers

Answers

Answer from: amandanunnery33

Part 1: - 1.091 x 10⁴ J/mol.

Part 2: - 1.137 x 10⁴ J/mol.

Explanation:

Part 1: At standard conditions:

At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:

I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.

Answer from: 25jzaldivar

a. ΔG°rxn at standard conditions : -1.09.10⁴ J/mol

b. ΔG°rxn at PICl= 2.63atm ; PI2= 0.324atm ; PCl2= 0.217atm = -1.14.10⁴ J/mol

Further explanation

The equilibrium constant is the ratio of the concentration or pressure between the result of the reaction / product and the reactant with each reaction coefficient raised

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

$\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}$

Whereas the equilibrium constant is based on partial pressure (Kp)

$\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}$

The value of Kp and Kc can be linked to the formula

$\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}$

R = gas constant = 0.0821 L.atm / mol.K

Δn = number of product coefficients-number of reactant coefficients

Gibbs (Free) Energy = ΔGrxn when connected to Kc / Kp:

ΔG°rxn is the standard Gibbs free energy of reaction,

ΔGrxn = ΔG°rxn + RTlnQ

At equilibrium, Q = K and ΔGrxn = 0

ΔG°rxn = -RTlnK

a. Standard condition (T = 298 K)

ΔG°rxn = -RTlnK

ΔG°rxn = - 8,314. 298 ln 81.9 = -10914.94 J / mol = -1.09.10⁴ J/mol

b. PICl = 2.63 atm; PI2 = 0.324 atm; PCl2 = 0.217 at m.

$Kp=\frac{PICl^2}{(PI_2)(PCl_2)}$

$= \frac{2.63^2}{0.324.0.217}$

Kp = 98.3799

ΔG°rxn = -RTlnK

ΔG°rxn = - 8,314. 298 ln 98.3799

ΔG°rxn = -11369.1728 J/mol = -1.14.10⁴ J/mol

Learn more

calculate kc for reaction 2 at the same temperature.

link

the ka reaction of hcn

link

the three most acidic hydrogen atoms

link

Keywords : kc, kp, ΔGrxn,Gibbs (Free) Energy, standard conditions

Consider the reaction: i2(g)+cl2(g)⇌2icl(g) kp= 81.9 at 25 ∘c. calculate δgrxn for the reaction at

Answer from: Quest

8.7 degrees celsius and 15.6 degrees fahrenheit
This is an environmental science question. what are the average annual temperatures of alice spring

This is an environmental science question. what are the average annual temperatures of alice spring

Answer from: Quest

Ibelieve its because the stove is a cleaner burning fuel

Another question on Chemistry

Chemistry, 22.06.2019 07:30

In the particles are arranged in a regular, repeating pattern. a)a crystalline liquid b)a crystalline solid c)all gases d)all solids

Answers: 2

Answer

Chemistry, 23.06.2019 00:30

In a ball-and-stick molecular model, what do the sticks represent?

Answers: 1

Answer

Chemistry, 23.06.2019 00:50

Which of the following warnings would an agricultural chemist tell a farmer who wants to recycle his or her own ammonia? recycling ammonia is a difficult process that sometimes takes weeks. recycling ammonia requires a degree in biochemistry or a related field. recycling ammonia can be harmful because it is highly flammable and toxic. recycling ammonia costs too much money considering the price of the necessary chemicals.

Answers: 1

Answer

Chemistry, 23.06.2019 10:00

Describe the basic structure of the atom

Answers: 1

Answer

You know the right answer?

Consider the reaction: i2(g)+cl2(g)⇌2icl(g) kp= 81.9 at 25 ∘c. calculate δgrxn for the reaction at...

Questions