Gthe standard emf for the cell using the overall cell reaction below is +0.48 v: zn (s) + ni2+ (aq) → zn2+ (aq) + ni (s) the emf generated by the cell when [ni2+] = 2.80 m and [zn2+] = 0.100 m is v. the standard emf for the cell using the overall cell reaction below is +0.48 v: (s) + (aq) (aq) + (s) the emf generated by the cell when [] = 2.80 m and [] = 0.100 m is v. 0.44 0.39 0.52 0.50 0.57

true

hope that

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

answermeridional ;