Asample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. which compounds could the sample be? ch3ch3ch202 c2h5oh c4h10o2 c4h12o2 and ch3ch3ch2ooh

C₄H₁₀O₂

Explanation:

Parameters given:

Percentage composition of Carbon = 52.14%

                                               Hydrogen = 13.13%

                                               Oxygen = 34.73%

From the given data, we can simply obtain the empirical formula of the compound which is the simplest formula of the compound. From the empirical formula, we can check other combining ratios of the compound.

To find the empirical formula of the compound:

Solution

                                                              C                        H                      O

% mass of elements                        52.14                   13.13                34.73

Moles                                               52.14/12              13.13/1            34.73/16

                                                           4.345                 13.13                 2.171

Dividing by the smallest              4.345/ 2.171       13.13/2.171         2.171/2.171

                                                                 2                        6                        1

The empirical formula of the compound is expressed as C₂H₆O

The molecular formula would be any factor that would give whole number ratios. The simplest number would be 2:

Molecular formula = 2(C₂H₆O) = C₄H₁₂O₂      

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

the answer is b. dilution