What is the total mass of copper consumed when 16.0 moles of water are produced? 3cu + 8hno3 → 3cu(no3)2 + 2no + 4h2o

762.55 g.

Explanation:

3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O.

It is clear that 3 mol of Cu reacts with 8 mol of HNO₃ to produce 3 mol of Cu(NO₃)₂, 2 mol of NO, and 4 mol of H₂O.

Using cross multiplication:

3 mol of Cu produce → 4 mol of H₂O, from stichiometry.

??? mol of Cu produce → 16 mol of H₂O.

∴ no. of moles of Cu needed = (3 mol)(16 mol)/(4 mol) = 12 mol.

∴ mass of Cu = (no. of moles)(atomic mass of Cu) = (12 mol)(63.546 g/mol) = 762.55 g.

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