If the pressure at a depth of 8 ft below the surface of a stagnant fluid is 3.5 psi, what will the pressure of the liquid be at a depth of 48 ft below the surface?

Answer : The pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.

Explanation : Given,

The pressure of the liquid at depth 8 ft = 3.5 psi

Now we have to calculate the pressure of the liquid at depth 28 ft.

According to the question,

As, the depth of 8 ft below the surface of a stagnant fluid has pressure = 3.5 psi

So, the depth of 48 ft below the surface of a stagnant fluid has pressure =

Therefore, the pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b

12 is it do you think so