How many grams of br are required to react completely with 29.5 g of no? 2no+br2- 2nobr

78.54 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

According to stoichiometry :

2 moles of react with 1 mole of

0.98 moles of react with = moles of

Mass of

Thus 78.54 g of are required to react completely with 29.5 g of NO.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa