How many liters of ammonia are required to change 34.9 l of nitrogen monoxide to nitrogen gas? assume 100% yield and that all gases are measured at the same temperature and pressure.

23.27 L

Explanation:

The balanced reaction of ammonia and nitrogen monoxide is shown below as:

4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)

Given that:

Volume of nitrogen monoxide = 34.9 L

Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.

So,

6 L of nitrogen monoxide reacts with 4 L of ammonia.

1 L of nitrogen monoxide reacts with 4/6 L of ammonia.

34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.

Amount of ammonia required = 23.27 L

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