Consider the following reaction: 2nobr(g) 2no(g) + br2(g)if 0.412 moles of nobr(g), 0.678 moles of no, and 0.224 moles of br2 are at equilibrium in a 10.3 l container at 516 k, the value of the equilibrium constant, kc, is:

Explanation: The given chemical reaction is:

Equilibrium constant (Kc) in general is written as:

Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

  = 0.040 M

  = 0.0658 M

  = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole