Determine the normality of the following solutions note the species of interest is h 95 g of po4 3- in 100ml solution

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

or,

First we have to calculate the equivalent weight of solute.

Molar mass of solute = 94.97 g/mole

Now we have to calculate the normality of solution.

Therefore, the normality of the solution is, 30.006 N

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

the increase of protons   hope this